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Pociagi potrzebuja 30 minut aby sie zderzyc gdyz pociag A poruszjac sie ze stala predkoscia 160 km/h po 30 minutach pokona 80 km
pociag B poruszajac sie ze stala predkoscia 120 km/h pokona w 30 minut 60 km
80 + 60 = 140
Pracownik poruszajac sie ze stala predkoscia 14 km/h pokona w ciagu 30 minut 7 km a ma pokonac dystan 6300 m czyli po 27 minutach zdazy przelaczyc semafor i uratowac pociagi przed zdarzeniem
nope
no he is way to slow
he will make it,
14km/60 => 233,33 m/s
so
6300m he will reach in 27mins
faster train will make 80km in 30mins
slower train will make 60km in 30mins
80+60=140km
trains will meet in 30min
It will take him 27 minutes (.45 hours) to cover the 6300m. In that time Train A will travel 72 km and Train B will travel 54 leaving them 14 km apart when the itch is thrown.
Yes he will be in time. Trains will colide in 0,5h 140km/(160+120). Supervisor will run for 0,45h 6,3/14. 0,5h>0,45h
The trains could collide in half an hour. The supervisor runs at 14,000 metres an hour so will arrive at the switches well within time to stop both trains.
HOWEVER modern signalling, even the old British block signalling system, would not allow this issue to arise.
Yes, became go to the switch in 27 minutes
The supervisor runs at 14 km/h.
The swith is at 6.3 km
He needs 0.45 h to reach it (6.3/14 = 0.45)
The distance between the trains is: 140 km
The trains run at 160 km/h and 120 km/h. The are approaching at 280 km/h
They will be in contact in 0.5 h (140 / 280 = 0.5)
The supervisor can switch BEFORE the collision because he needs 0.45 h whereas the collision could happen after (0.5h)
le régulateur arrivera à temps, les trains vont mettre 1h pour se rejoindre alors que lui sera arrivé en moins d'une demie heure
yes, he managed to avoid the crash.
Explanaition:
He took 27 minutes to get the switch.
Mean while train A do 72 km, and train B 54 km. 72+54=126 less then 140.
Yes , he will be on time because :
He need 0,45 h for goes to switch 6,5km/14km/h =0,45h;
Trains for this time go 126 km - this is 0,45h*(120+160)km/h=126km
Beacouse 126km < 140km - that is ok .
Controller will arrive after 27 minutes at the security switch.
Based on their speed, the trains will collide in 30 minutes.
As a conclusion, we are gratefull the controller is quick enough to save both trains.
The two trains will collapse in 30 minutes. Train A will do 80km et train will do 60 km in 30 minutes so 140km covered. In 30 minutes, the supervisor runs 7km and he has 6.3km to run. So he'll get there just in time.
He will arrive on time.
He needs 27 min to arrive (0.45h) to manual switch. In that time, Train A will do 72km and train B 54km. That made a total distance of 126km. Less tan the 140km between them.
çarpışmazlar . iki tren 30 dakika sonra çarpışcak,ama görevli 27 dakika sonra orada olur ve çarpışmayı önler.
they do not collide.two trains collide after 30 minutes,but the attendant will be therem after 27 minutes and prevents the collision..
Display Moreдавайте сначала посмотрим на поезда: используя нерелятивистскую механику, мы видим, что с точки зрения одного поезда другой поезд движется со скоростью 160+120=280 км/ч. Следовательно, расстояние до другого поезда (140 км) будет покрыто ровно за 30 минут. Супервайзер должен пробежать 6,3 км со скоростью 14 км/ч, при этом занимает 6,3 / 14=0,45 ч=27мин. Так как 27 & lt;30, супервизор может потянуть переключатель, прежде чем он увидит, что поезда сталкиваются.< / p>
< / p>нам нужно только надеяться, что переключатель находится в правильном месте...< / p> <человеческие ресурсы> Добавление :при рассмотрении релятивистского случая, в рамке переключателя, переключатель будет вытягиван в 27мин (таком же вычислении).< / p>
в раме каждого поезда скорость движения другого поезда немного меньше, чем 280 км/ч (это (120+160)/(1+120*160/С^2), где с^2-скорость света).< / p>
в рамках поезда расстояние, которое необходимо покрыть, будет сокращено на коэффициент γ (который отличается для обоих поездов), поэтому для ПОЕЗДА Столкновение происходит на коэффициент γ раньше, чем для коммутатора. Однако часы в каждом поезде работают медленнее, чем часы в коммутаторе, на тот же фактор γ. Таким образом, поезд видит, что переключатель тянется раньше на фактор γ, чем переключатель видит его.< / p> мы приходим к выводу, что оба поезда видят, что переключатель тянется раньше, чем они "видят" столкновение, на самом деле относительность поможет избежать столкновения.< / p>
< / p> < p>PS: γ=1 / sqrt(1-v^2 / c^2), где v-скорость движения поезда, а c-скорость света< / p>
:большой палец вверх:
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2 May 1994
I can't wait until school is over. Only two more years and I can finally begin a new chapter of my life. Today, dad helped me out with my homework again. This maths exercise was really confusing, but he helped me figure out how to solve it. He's really good with numbers. No wonder he's so successful with his shop. Yesterday, he asked me again if I wanted to take over his shop. I know it'd make him happy, but I have my own plans and dreams. Once I graduate from school, I'm going to become a top manager and create my own business. I can't wait! Time to sleep now. But first I'll review this maths exercise once again, just to make sure I can present the right answers in class tomorrow.
Maths task:
Due to a technical error, two trains were accidently assigned to the same rail track and are now approaching each other. The communication system of both trains is broken and the conductors don't know about the imminent danger they're in.
By the time a supervisor at one of the offices notices the problem, the trains are only 140 km away from each other. The speed of train A is 160 km/h; the speed of train B is 120 km/h.
There's a manual switch that could stop both trains from colliding, but the supervisor is 6,300 metres away from it and he needs to get there first. If he runs at an average speed of 14 km/h, will he be in time to save the trains?
Task: Solve the math exercise.
- 3 points for the correct answer
- 7 points for the correct explanation
Yes he will be able to save the trains ,
explanation: the trains will meet in 30 minutes , train A needs 30 min for 80KM and train B needs 30 min fpr 60KM , together 140KM
the superviser needs 27 minutes for the 6300 meters , so he will be in time
