Posts by Dutcher

• Chapter 5 - Solution cognitive test

Q15: Read the question, take it literally. "Between" means "Between", so only the pages of the middle book count.

The pages of the other books are on top of each other.

Q10: No, you keep 3 squares plus a loose match. Answer D gives you just 3 squares.

Take away the bottom right 2 corner matches and the top middle match.

I do have a question about # 13. I gat to 65 minutes minimum. The 5 minute walker takes the torch back 2x:

25 + 5, 20 + 5, & 10 = 65 minutes. I don't see how it is possible to get them all across the bridge in 60 minutes?

• Chapter 4

Answer: Option 4 Move the passengers onto the Napping Neptune

Explanation:

Jumbo Jupiter: 620 km distance / 300 kph speed = 2 hours & 4 minutes travel time. 6:30pm departure = normally 8:34pm arrival, well in time for passengers to make their connection in Hicksburg at midnight.

Options:

1) Mechanic fix and 50% reimbursement to all passengers will cost \$8k but will also delay the passengers 4 hours arriving 40 minutes past midnight (6:30pm + 2:04h travel time + 4 hour delay for fix= 00:34am), causing them to miss their connection and resulting in an additional cost of \$30k to pay for their overnight stay!

\$8k + \$30k = \$38k (plus unhappy passengers!)

2) Half of the ticket price was \$8k above, so cancelling the entire trip will result in a \$16k compensation at full price (plus probably also unhappy passengers!).

3) Motor exchange will cost \$12k & a 90 minute delay. This will still get the passengers to their destination on time: 6:30pm + 1:30h delay + 2:04h travel time = 10:04pm, arriving almost 2 hours before midnight, well in time for the passengers to make their connection.

4) Napping Neptune speed is 40% of 300kph = 120kph. Travel time = 620km / 120kph = 5 hours & 10 minutes.

6:30pm departure + 5:10h travel = 11:40pm arrival, which leaves 20 minutes for the passengers to still make their connection and with no further cost to the company! \$0

Options 1 & 2 do not get the passengers to their destination on time and also result in the highest extra cost to the company. These options should therefore not be considered. Always keep your customers happy!

Option 3 gets the passengers to their destination the quickest (smallest delay) but will still cost the company \$12k.

Option 4 Moving them to the Napping Neptune still gets the passengers to their destination on time and at the lowest (\$0) cost to the company. This is therefore the best option to take.

Dutcher

NL01 Stoomketel

• Chapter 3

Not sure if we are supposed to give our domain & server name?

I forgot it in my answer above ^ : NL01 Stoomketel

• Chapter 3

Explanation:

Priority Analysis Scoring - Point ranking system weighted by priority:

x1 Punct (1,2,3 Pts) x2 Cost (2,4,6 Pts) x4 Qual (4,8,12 Pts) Total Points
Mecha-Heads 1 Point 6 Points 4 points 11 Points
Swiss Metal 2,5 Points 2 Points 12 Points 16,5 Points
General Machines 2,5 Points 4 Points 8 points 14,5 Points
• Chapter 2

1 = 3 (No difference)

2 = 4 (Scissors)

3 = 1 (A)

4 = 2 (B)

5 = 1 (A Sand)

6 = 3 (10 rotations Anti-Clockwise)

7 = 4 (2,5 Kg)

8 = 3 (20cm/3)

9 = 1 (Acceleration will still be A)

10 = 2 (Less than 5 cm)

Dutcher

NL01 Stoomketel